An isoptic is the set of points for which two tangents of a given curve meet at a fixed angle .
An isoptic of twoplane curves is the set of points for which two tangents meet at a fixed angle.
Thales' theorem on a chord can be considered as the orthoptic of two circles which are degenerated to the two points and.
Orthoptic of a parabola
Any parabola can be transformed by a rigid motion into a parabola with equation. The slope at a point of the parabola is. Replacing gives the parametric representation of the parabola with the tangent slope as parameter: The tangent has the equation with the still unknown, which can be determined by inserting the coordinates of the parabola point. One gets If a tangent contains the point, off the parabola, then the equation holds, which has two solutions and corresponding to the two tangents passing. The free term of a reduced quadratic equation is always the product of its solutions. Hence, if the tangents meet at orthogonally, the following equations hold: The last equation is equivalent to which is the equation of the directrix.
Let be the ellipse of consideration. ' The tangents of ellipse at neighbored vertices intersect at one of the 4 points, which lie on the desired orthoptic curve. ' The tangent at a point of the ellipse has the equation . If the point is not a vertex this equation can be solved: Using the abbreviations and the equation one gets: Hence and the equation of a nonvertical tangent is Solving relations for and respecting leads to the slope depending parametric representation of the ellipse: If a tangent contains the point, off the ellipse, then the equation holds. Eliminating the square root leads to which has two solutions corresponding to the two tangents passing. The free term of a reduced quadratic equation is always the product of its solutions. Hence, if the tangents meet at orthogonally, the following equations hold: The last equation is equivalent to From ' and ' one gets:
The intersection points of orthogonal tangents are points of the circle .
Hyperbola
The ellipse case can be adopted nearly exactly to the hyperbola case. The only changes to be made are to replace with and to restrict to. Therefore:
The intersection points of orthogonal tangents are points of the circle, where.
Orthoptic of an astroid
An astroid can be described by the parametric representation From the condition one recognizes the distance in parameter space at which an orthogonal tangent to appears. It turns out that the distance is independent of parameter, namely. The equations of the tangents at the points and are respectively: Their common point has coordinates: This is simultaneously a parametric representation of the orthoptic. Elimination of the parameter yields the implicit representation Introducing the new parameter one gets Hence we get the polar representation of the orthoptic. Hence:
The orthoptic of an astroid is a quadrifolium.
Isoptic of a parabola, an ellipse and a hyperbola
Below the isotopics for angles are listed. They are called -isoptics. For the proofs see [|below].
Equations of the isoptics
; Parabola: The -isoptics of the parabola with equation are the branches of the hyperbola The branches of the hyperbola provide the isoptics for the two angles and . ; Ellipse: The -isoptics of the ellipse with equation are the two parts of the degree-4 curve . ; Hyperbola: The -isoptics of the hyperbola with the equation are the two parts of the degree-4 curve
Proofs
; Parabola: A parabola can be parametrized by the slope of its tangents : The tangent with slope has the equation The point is on the tangent if and only if This means the slopes, of the two tangents containing fulfil the quadratic equation If the tangents meet at angle or, the equation must be fulfilled. Solving the quadratic equation for, and inserting, into the last equation, one gets This is the equation of the hyperbola [|above]. Its branches bear the two isoptics of the parabola for the two angles and. ; Ellipse: In the case of an ellipse one can adopt the idea for the orthoptic for the quadratic equation Now, as in the case of a parabola, the quadratic equation has to be solved and the two solutions, must be inserted into the equation Rearranging shows that the isoptics are parts of the degree-4 curve: ; Hyperbola: The solution for the case of a hyperbola can be adopted from the ellipse case by replacing with . To visualize the isoptics, see implicit curve.