Bound state


In quantum physics, a bound state is a quantum state of a particle subject to a potential such that the particle has a tendency to remain localised in one or more regions of space. The potential may be external or it may be the result of the presence of another particle; in the latter case, one can equivalently define a bound state as a state representing two or more particles whose interaction energy exceeds the total energy of each separate particle. One consequence is that, given a potential vanishing at infinity, negative-energy states must be bound. In general, the energy spectrum of the set of bound states is discrete, unlike free particles, which have a continuous spectrum.
Although not bound states in the strict sense, metastable states with a net positive interaction energy, but long decay time, are often considered unstable bound states as well and are called "quasi-bound states". Examples include certain radionuclides and electrets.
In relativistic quantum field theory, a stable bound state of particles with masses corresponds to a pole in the S-matrix with a center-of-mass energy less than. An unstable bound state shows up as a pole with a complex center-of-mass energy.

Examples

Let be a complex separable Hilbert space, be a one-parameter group of unitary operators on and be a statistical operator on. Let be an observable on and be the induced probability distribution of with respect to on the Borel σ-algebra of. Then the evolution of induced by is bound with respect to if, where.
More informally, a bound state is contained within a bounded portion of the spectrum of. For a concrete example: let and let be position. Given compactly-supported and.
Let have measure-space codomain. A quantum particle is in a bound state if it is never found “too far away from any finite region,” i.e. using a wavefunction representation,
Consequently, is finite. In other words, a state is a bound state if and only if it is finitely normalizable.
As finitely normalizable states must lie within the discrete part of the spectrum, bound states must lie within the discrete part. However, as Neumann and Wigner pointed out, a bound state can have its energy located in the continuum spectrum. In that case, bound states still are part of the discrete portion of the spectrum, but appear as Dirac masses in the spectral measure.

Position-bound states

Consider the one-particle Schrödinger equation. If a state has energy, then the wavefunction satisfies, for some
so that is exponentially suppressed at large. Hence, negative energy-states are bound if V vanishes at infinity.

Requirements

A boson with mass mediating a weakly coupled interaction produces an Yukawa-like interaction potential,
where, is the gauge coupling constant, and is the reduced Compton wavelength. A scalar boson produces a universally attractive potential, whereas a vector attracts particles to antiparticles but repels like pairs. For two particles of mass and, the Bohr radius of the system becomes
and yields the dimensionless number
In order for the first bound state to exist at all,. Because the photon is massless, is infinite for electromagnetism. For the weak interaction, the Z boson's mass is, which prevents the formation of bound states between most particles, as it is the proton's mass and the electron's mass.
Note however that if the Higgs interaction didn't break electroweak symmetry at the electroweak scale, then the SU weak interaction would become confining.