Arthur–Merlin protocol
In computational complexity theory, an Arthur-Merlin protocol is an interactive proof system in which the verifier's coin tosses are constrained to be public. This notion was introduced by. proved that all languages with interactive proofs of arbitrary length with private coins also have interactive proofs with public coins.
Given two participants in the protocol called Arthur and Merlin respectively, the basic assumption is that Arthur is a standard computer equipped with a random number generating device, while Merlin is effectively an oracle with infinite computational power ; but Merlin is not necessarily honest, so Arthur must analyze the information provided by Merlin in response to Arthur's queries and decide the problem itself. A problem is considered to be solvable by this protocol if whenever the answer is "yes", Merlin has some series of responses which will cause Arthur to accept at least of the time, and if whenever the answer is "no", Arthur will never accept more than of the time. Thus, Arthur acts as a probabilistic polynomial-time verifier, assuming it is allotted polynomial time to make its decisions and queries.
MA
The simplest such protocol is the 1-message protocol where Merlin sends Arthur a message, and then Arthur decides whether to accept or not by running a probabilistic polynomial time computation. Merlin does not have access to Arthur's coin tosses in this protocol, since it is a single-message protocol and Arthur tosses his coins only after receiving Merlin's message. This protocol is called MA. Informally, a language L is in MA if for all strings in the language, there is a polynomial sized proof that Merlin can send Arthur to convince him of this fact with high probability, and for all strings not in the language there is no proof that convinces Arthur with high probability.Formally, the complexity class MA is the set of decision problems that can be decided in polynomial time by an Arthur–Merlin protocol where Merlin's only move precedes any computation by Arthur. In other words, a language L is in MA if there exists a polynomial-time deterministic Turing machine M and polynomials p, q such that for every input string x of length n = |x|,
- if x is in L, then
- if x is not in L, then
- if x is not in L, then
AM
The complexity class AM is the set of decision problems that can be decided in polynomial time by an Arthur-Merlin protocol with two messages. There is only one query/response pair: Arthur tosses some random coins and sends the outcome of all his coin tosses to Merlin, Merlin responds with a purported proof, and Arthur deterministically verifies the proof. In this protocol, Arthur is only allowed to send outcomes of coin tosses to Merlin, and in the final stage Arthur must decide whether to accept or reject using only his previously generated random coin flips and Merlin's message.In other words, a language L is in AM if there exists a polynomial-time deterministic Turing machine M and polynomials p, q such that for every input string x of length n = |x|,
- if x is in L, then
- if x is not in L, then
- if x is not in L, then
The complexity class AM is the set of problems that can be decided in polynomial time, with k queries and responses. AM as defined above is AM. AM would start with one message from Merlin to Arthur, then a message from Arthur to Merlin and then finally a message from Merlin to Arthur. The last message should always be from Merlin to Arthur, since it never helps for Arthur to send a message to Merlin after deciding his answer.
Properties
- Both MA and AM remain unchanged if their definitions are changed to require perfect completeness, which means that Arthur accepts with probability 1 when x is in the language.
- For any constant k ≥ 2, the class AM is equal to AM. If k can be polynomially related to the input size, the class AM is equal to the class, IP, which is known to be equal to PSPACE and is widely believed to be stronger than the class AM.
- MA is contained in AM, since AM contains MA: Arthur can, after receiving Merlin's certificate, flip the required number of coins, send them to Merlin, and ignore the response.
- It is open whether AM and MA are different. Under plausible circuit lower bounds, they are both equal to NP.
- AM is the same as the class BP.NP where BP denotes the bounded-error probabilistic operator. Also, ' is a subset of MA. Whether MA is equal to ' is an open question.
- The conversion to a private coin protocol, in which Merlin cannot predict the outcome of Arthur's random decisions, will increase the number of rounds of interaction by at most 2 in the general case. So the private-coin version of AM is equal to the public-coin version.
- MA contains both NP and BPP. For BPP this is immediate, since Arthur can simply ignore Merlin and solve the problem directly; for NP, Merlin need only send Arthur a certificate, which Arthur can validate deterministically in polynomial time.
- Both MA and AM are contained in the polynomial hierarchy. In particular, MA is contained in the intersection of Σ2P and Π2P and AM is contained in Π2P. Even more, MA is contained in subclass S2P |, a complexity class expressing "symmetric alternation". This is a generalization of Sipser–Lautemann theorem.
- AM is contained in NP/poly, the class of decision problems computable in non-deterministic polynomial time with a polynomial size advice. The proof is a variation of Adleman's theorem.
- MA is contained in PP; this result is due to Vereshchagin.
- MA is contained in its quantum version, QMA.
- AM contains the problem of deciding if two graphs are not isomorphic. The protocol using private coins is the following and can be transformed to a public coin protocol. Given two graphs G and H, Arthur randomly chooses one of them, and chooses a random permutation of its vertices, presenting the permuted graph I to Merlin. Merlin has to answer if I was created from G or H. If the graphs are nonisomorphic, Merlin will be able to answer with full certainty. However, if the graphs are isomorphic, it is both possible that G or H was used to create I, and equally likely. In this case, Merlin has no way to tell them apart and can convince Arthur with probability at most 1/2, and this can be amplified to 1/4 by repetition. This is in fact a zero knowledge proof.
- If AM contains coNP then PH = AM. This is evidence that graph isomorphism is unlikely to be NP-complete, since it implies collapse of polynomial hierarchy.
- It is known, assuming ERH, that for any d the problem "Given a collection of multivarariate polynomials each with integer coefficients and of degree at most d, do they have a common complex zero?" is in AM.
Footnotes