1968 CONCACAF Champions' Cup
The 1968 CONCACAF Champions' Cup was the 4th edition of the annual international club football competition held in the CONCACAF region, the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region.
The tournament was played by 10 teams of 10 nations: Netherlands Antilles, Bermuda, El Salvador, United States, Guatemala, Mexico, Honduras, Suriname, Nicaragua, Costa Rica.
It was played from 26 May till 1 December 1968 under the home/away match system.
The tournament was split in 3 zones, each one qualifying the winner to the final tournament, where the winners of the Central and Caribbean zones played a semi-final to decide who was going to play against the Northern champion in the final. The final was scratched and Toluca were declared champions after both semi-finalists, Aurora and Transvaal, were ejected from the competition due to crowd violence.
Club Deportivo Toluca from Mexico won the final, and became for the first time in its history CONCACAF champion.
Caribbean zone
- Transvaal won 4–2 on aggregate score.
Northern zone
First round
- NY Greek Americans won 4–3 on aggregate score.
Second round
- Toluca won 7–3 on aggregate score.
Central American Zone
First Round
- Aurora won 2–1 on aggregate score.
- Olimpia won 3–1 on aggregate score.
Second Round
- Aurora won 5–1 on aggregate score.
Semifinals
- At the end of the 2nd leg, Transvaal fans invaded the pitch, but after Aurora fans did the same, a mass brawl broke out between the two sets of fans; both teams were ejected from the competition.
Final
Champion
| CONCACAF Champions' Cup 1968 Champion |
 |
| Toluca First Title |