1960 United States House of Representatives elections
The 1960 United States House of Representatives elections was an election for the United States House of Representatives in 1960, which coincided with the election of President John F. Kennedy and was the first house election to feature all 50 U.S. states. In spite of Kennedy's victory, his Democratic Party lost 20 seats to the Republican Party. That may have been a reaction to the major Democratic gains in the previous election. An end to the economic downturn of the mid-1950s was also a factor. Still, the Democrats retained a clear majority in the House.
There were 437 seats: 435 from the reapportionment in accordance with the 1950 census, and 1 seat for each of the new states of Alaska and Hawaii.Overall results
Source: In these special elections, the winner was seated during 1960 or before January 3, 1961; ordered by election date, then state, then district.Alabama
Alaska
Arizona
Arkansas
California
Colorado
Connecticut
Delaware
Florida
Georgia
Hawaii
Idaho
Illinois
Indiana
Iowa
Kansas
Kentucky
Louisiana
Maine
Maryland
Massachusetts
Michigan
Minnesota
Mississippi
Missouri
Montana
Nebraska
Nevada
New Hampshire
New Jersey
New Mexico
New York
North Carolina
North Dakota
Ohio
Oklahoma
Oregon
Pennsylvania
Rhode Island
South Carolina
South Dakota
Tennessee
Texas
Utah
Vermont
Washington
West Virginia
Wisconsin
Wyoming
